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Question:
an apache helicopter of enemy is flying along the curve given by=x^2 plus 7. a soldier placed at (3,7) wants to shoot down the helicopter when it is nearest to him.find the nearest distance.
Answer:

Given that an apache helicopter of enemy is flying along the curve given by = x2 + 7 

A soldier placed at (3,7) wants to shoot down the helicopter when it is nearest to him.

Now, the distance of the point from the soldier is S = √[ (x-3)2 + (y-7)2 ]

Since the point lies on the curve y = x2 + 7 ..............1

     S = √[ (x-3)2 + (x2 + 7 - 7)2 ]

=> S = √(x4 + x2 - 6x + 9)

When the distance is maximum/minimum,

dS/dx = 0

(4x3 + 2x - 6) / √(x4 + x2 - 6x + 9) = 0

=> 4x3 + 2x - 6 = 0

=> 2x3 + x -3 = 0

=> (x-1)*(2x2 + 2x + 3) = 0

The solutions to the above equation are

x = 1, -0.5 ± i*0.5√5

Since the solution cannot have any complex roots.

Hence, x = 1 is the abscissa of the nearest point to the soldier.

From equation 1, we get

y = 12 + 7

=> y = 8

So, the nearest point is (1,8)

Now, nearest distance S = √[ (1-3)2 + (8-7)2 ]

=> S = √[ (-2)2 + (1)2 ]

=> S = √[4 + 1]

=> S = √5 units

 

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